A) \[4.07\times {{10}^{4}}V\]
B) \[8.15\times {{10}^{4}}V\]
C) \[8.15\times {{10}^{3}}V\]
D) \[4.07\times {{10}^{5}}V\]
Correct Answer: B
Solution :
[b] \[{{\lambda }_{p}}=\frac{0.286}{\sqrt{V}}\overset{\text{o}}{\mathop{\text{A}}}\,\] \[{{\lambda }_{p}}={{10}^{-13}}m={{10}^{-3}}\overset{\text{o}}{\mathop{\text{A}}}\,\] \[{{10}^{-3}}=\frac{0.286}{\sqrt{V}}\] \[\Rightarrow V={{(0.286)}^{2}}\times {{10}^{6}}\] \[=0.817\times {{10}^{6}}\] \[\Rightarrow 8.15\times {{10}^{4}}\] volt
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