A) \[{{C}_{6}}{{H}_{6}}+C{{l}_{2}}\,\xrightarrow{FeC{{l}_{3}}}\]
B) \[{{C}_{6}}{{H}_{6}}+HOCl\,\xrightarrow{{{H}^{+}}}\]
C) \[{{C}_{6}}{{H}_{6}}+I-Cl\,\xrightarrow{ZnC{{l}_{2}}}\]
D) \[{{C}_{6}}{{H}_{6}}+C{{l}_{2}}\,\xrightarrow{AlC{{l}_{3}}}\]
Correct Answer: B
Solution :
Due to absence of lewis acid chlorination of benzene is not possible.
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