A) \[3\text{ }\mu C\]
B) \[\text{6 }\mu C\]
C) \[\text{12 }\mu C\]
D) \[\text{24 }\mu C\]
Correct Answer: B
Solution :
[b] At steady state. No current will flow through capacitor. So \[i=\frac{E}{{{R}_{2}}+r}=\frac{5}{4+1}=1A\] Potential difference a cross capacitor \[=i\times {{R}_{2}}\] \[=1\times 4=4V\] Charge on each capacitor \[=\left( \frac{C}{2} \right)\times 4\] \[=\left( \frac{3}{2} \right)\times 4=6\mu C\]You need to login to perform this action.
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