question_answer

When \[KMn{{O}_{4}}\] acts as an oxidising agent and ultimately forms\[{{\left[ Mn{{O}_{4}} \right]}^{2-}}\], \[Mn{{O}_{2}}\], \[M{{n}_{2}}{{O}_{3}}\], \[M{{n}^{2+}}\] then the number of electrons transferred in each case respectively is

A) 4, 3, 1, 5          

B)        1, 5, 3, 7

C) 1, 3, 4, 5                      

D) 3, 5, 7, 1.

Correct Answer: C

Solution :