A) \[1.1\,mA\]
B) \[1.01\,mA\]
C) \[0.01\,mA\]
D) \[10\,mA\]
Correct Answer: B
Solution :
\[\beta =\frac{\Delta {{i}_{c}}}{\Delta {{i}_{b}}},\] so \[\Delta {{i}_{b}}=\frac{1\times {{10}^{-3}}}{100}=0.01\,mA\] \[\Delta {{i}_{e}}=\Delta {{i}_{b}}+\Delta {{i}_{c}}=0.01+1=1.01\,mA\]
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