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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 3

  • question_answer
                                                                             A photon of \[1.7\times {{10}^{-13}}\] joule is absorbed by a material under special circumstances. The correct statement is

    A) Electrons of the atom of absorbed material will go the higher energy states

    B) Electron and positron pair will be created

    C) Only positron will be produced

    D) Photoelectric effect will occur and electron will be produced

    Correct Answer: B

    Solution :

    For electron and positron pair production, minimum energy is\[1.02\,MeV\]. Energy of photon is given \[1.7\times {{10}^{-3}}J=\frac{1.7\times {{10}^{-13}}}{1.6\times {{10}^{-19}}}=1.06\,MeV.\] Since energy of photon is greater than \[1.02\text{ }MeV.\] so electron positron pair will be created.


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