A) 1/2
B) 2
C) 2/3
D) 3/2
Correct Answer: D
Solution :
[d] \[\frac{{{B}_{1}}}{{{B}_{2}}}=\frac{\frac{{{\mu }_{0}}}{2\pi }\left( \frac{{{i}_{1}}}{d}-\frac{{{i}_{2}}}{d} \right)}{\frac{{{\mu }_{0}}}{2\pi }\left( \frac{{{i}_{1}}}{d}+\frac{{{i}_{2}}}{d} \right)}\]You need to login to perform this action.
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