A) 1/20
B) 1/100
C) 1
D) None of these (\[e/m=1.8\times {{10}^{14}}C/kg\] for an electron)
Correct Answer: C
Solution :
[c] For incident electron \[{{\lambda }_{1}}=\frac{h}{p}=\frac{h}{\sqrt{2km}}=\frac{h}{\sqrt{2mVe}}\] and shortest wavelength of X-rays is \[{{\lambda }_{2}}=\frac{hc}{Ve}\] \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{1}{c}\sqrt{\left( \frac{V}{2} \right)\left( \frac{e}{m} \right)}\] Substituting the value we get \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=1\]
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