A) \[N{{O}_{2}}\]
B) \[{{O}_{2}}\]
C) \[{{N}_{2}}\]
D) \[{{N}_{2}}O\]
Correct Answer: B
Solution :
\[Pb{{O}_{2}}\] is a powerful oxidizing agent and liberate \[{{O}_{2}}\] when treated with acids. \[2Pb{{O}_{2}}+4HN{{O}_{3}}\xrightarrow{{}}2Pb{{(N{{O}_{3}})}_{2}}+2{{H}_{2}}O+{{O}_{2}}\uparrow \]
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