A) 4
B) 8
C) 10
D) 12
Correct Answer: A
Solution :
[a] Hence \[{{\omega }_{1}}=100\pi \] and \[{{\omega }_{2}}=92\pi \]s Hence \[{{V}_{1}}=\frac{100\pi }{2\pi }=50\,Hz\] And \[{{V}_{2}}=\frac{92\pi }{2\pi }=46\,Hz\] \[\therefore \] Number of beats per second \[={{V}_{1}}-{{V}_{2}}\] \[=50-46=4\]You need to login to perform this action.
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