A) \[0\]
B) \[+1\]
C) \[+2\]
D) \[+3\]
Correct Answer: D
Solution :
Oxidation state of \[Cr\] in \[{{[Cr{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]}^{+}}\] Let it be x, \[1\times x+4\times 0+2\times (-1)=1\] Therefore \[x=3\].You need to login to perform this action.
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