A) \[2m{{v}_{0}}\hat{i}\]
B) \[\sqrt{2}m{{v}_{0}}(\hat{i}+\hat{j})\]
C) \[-2m{{v}_{0}}\hat{i}\]
D) \[\sqrt{2}m{{v}_{0}}(\hat{i}-\hat{j})\]
Correct Answer: C
Solution :
[c] The particle goes in a circular path in xy plane. \[\vec{r}.\vec{v}\] when \[\vec{r}{{\bot }_{r}}\vec{V}\] This happens when the particle has completed half circle (see figure) Change in momentum of particle \[\overrightarrow{\Delta p}=-2m{{v}_{0}}\hat{i}\] \[\therefore \] Impulse \[=-2m{{v}_{0}}\hat{i}\]You need to login to perform this action.
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