A) 13.6, 6.8, 8.4 eV
B) 13.6, 10.2, 3.4 eV
C) 13.6, 27.2, 40.8 eV
D) 13.6, 3.4, 1.5 eV
Correct Answer: D
Solution :
[d] \[{{E}_{T}}=-13.6\frac{{{Z}^{2}}}{{{n}^{2}}}\] I orbit for (H) \[Z=1,n=1\] \[{{E}_{T}}=-13.6eV\] II orbit for (H) \[Z=1,n=2\] \[{{E}_{T}}=-\frac{13.6}{4}=-3.4eV\] III orbit for (H) \[{{E}_{T}}=-\frac{13.6}{9}=-1.51\,eV\]You need to login to perform this action.
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