A) 1 : 2
B) 5 : 3
C) 1 : 1
D) 2 : 3
Correct Answer: B
Solution :
[b] \[CHO-CHOH-\underset{glu\cos e}{\mathop{CHOH}}\,-CHOH-CHOH-C{{H}_{2}}OH\]\[\xrightarrow{5HI{{O}_{4}}}HCOOH+HCHO+5HI{{O}_{3}}\] \[C{{H}_{2}}OH-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\underset{fructose}{\mathop{CHOH}}\,-CHOH-CHOH-C{{H}_{2}}OH\]\[\xrightarrow{5HI{{O}_{4}}}3HCOOH+2HCHO+5HI{{O}_{3}}+C{{O}_{2}}+{{H}_{2}}O\] \[\therefore \] molar ratio is 5 : 3You need to login to perform this action.
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