A) \[-1,-1,1\]
B) \[-1,-1,-1\]
C) \[1,1,1\]
D) \[1,-1,-1\]
Correct Answer: D
Solution :
Applying dimensional method: \[{{v}_{c}}={{\eta }^{x}}{{\rho }^{y}}{{r}^{z}}\] \[[{{M}^{0}}L{{T}^{-1}}]={{[M{{L}^{-1}}{{T}^{-1}}]}^{x}}{{[M{{L}^{-3}}{{T}^{0}}]}^{y}}{{[{{M}^{0}}L{{T}^{0}}]}^{z}}\] Equating powers both sides \[x+y=0;\] \[-x=-1\,\,\therefore x=1\] \[1+y=0\,\,\therefore \,\,y=-1\] \[-x-3y+z=1\] \[-1-3(-1)+z=1\] \[-1+3+z=1\] \[\therefore \,\,z=-1\]You need to login to perform this action.
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