A) Work done by the battery is half of the energy dissipated in the resistor
B) At \[t=\tau ,\,\,q=-CV/2\]
C) At \[t=2\tau ,\,\,q=CV(1-{{e}^{-2}})\]
D) At \[t=\frac{\tau }{2},\,q=CV\,(1-{{e}^{-1}})\]
Correct Answer: C
Solution :
Charge on the capacitor at any time t is given by \[q=CV(1-{{e}^{t/\tau }})\] at \[t=2\tau \] \[q=CV(1-{{e}^{-2}})\]You need to login to perform this action.
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