A) \[{{x}^{15}}\]
B) \[-{{2}^{5}}{{x}^{15}}\]
C) \[{{2}^{15}}{{x}^{5}}\]
D) \[{{2}^{5}}{{x}^{-15}}\]
Correct Answer: B
Solution :
[b] \[{{T}_{11}}_{(staiting)}{{=}^{25}}{{C}_{10}}{{2}^{15}}\left( \frac{1}{{{x}^{5}}} \right)\] \[{{T}_{11}}_{\left( enfing \right)}={{T}_{16\left( starting \right)}}\] \[={{-}^{25}}{{C}_{15}}{{2}^{10}}\left( \frac{1}{{{x}^{20}}} \right)\] Then \[\frac{{{T}_{11(starting)}}}{{{T}_{11(ending)}}}=-{{2}^{5}}{{x}^{15}}\]
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