A) \[\frac{Q}{2{{d}_{0}}}{{u}_{0}}\]
B) \[\frac{Q}{{{d}_{0}}}{{u}_{0}}\]
C) \[\frac{2Q}{{{d}_{0}}}{{u}_{0}}\]
D) \[\frac{Q}{3{{d}_{0}}}{{u}_{0}}\]
Correct Answer: A
Solution :
Let each plate moves a distance x from its initial position. Let q charge flows in the loop. Using Kirchoff?s voltage law \[\frac{\left( \frac{Q}{2}-q \right)\,({{d}_{0}}+x)}{{{\in }_{0}}A}-\frac{\left( \frac{Q}{2}+q \right)({{d}_{0}}-x)}{{{\in }_{0}}A}=0\] \[\therefore \,\,q=\frac{Qx}{2{{d}_{0}}};\] \[I=\frac{dq}{dt}=\frac{Q}{2{{d}_{0}}}\left( \frac{dx}{dt} \right)=\frac{Q}{2{{d}_{0}}}{{u}_{0}}\]You need to login to perform this action.
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