(I) \[PhCHO\] |
(II) |
(III) |
(IV) |
A) I > IV > II > III
B) III > II > IV > I
C) I > III > II > V
D) I > III > II > IV
Correct Answer: A
Solution :
[a] EDG (Me group) at \[o-,\] \[m-,\] and p-positions: At ortho-position, ED power of \[(Me-)\] group is more than p and m (due to \[+1\] effect and hyperconjugation effect). ED power of \[(Me-)\] group at ortho-position is slightly less than the \[Me\]groups at ortho-position (due to less \[+I\]effect, but equal hyperconjugative effect). So the order of ED power of \[(Me-)\] group is \[o>p>m-.\]NA is favoured by less-substituted EDG or more-substituted EDG or more-substituted EWG. So, the order of reactivity of \[PhMgBr\]with aromatic aldehyde isYou need to login to perform this action.
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