JEE Main & Advanced Sample Paper JEE Main - Mock Test - 43

  • question_answer
    The depth d at which the value of acceleration due to gravity becomes \[\frac{1}{n}\] times the value at the surface of the earth, is [R = radius of the earth]

    A) \[\frac{R}{n}\]  

    B)        \[R\left( \frac{n-1}{n} \right)\]

    C) \[\frac{R}{{{n}^{2}}}\]           

    D)        \[R\left( \frac{n}{n+1} \right)\]

    Correct Answer: B

    Solution :

    \[g'=g\left( 1-\frac{d}{R} \right)\Rightarrow \frac{g}{n}=g\left( 1-\frac{d}{R} \right)\] \[\Rightarrow \,\,d=\left( \frac{n-1}{n} \right)R\]


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