A) \[3.18\]
B) \[6.36\]
C) \[5.18\]
D) \[1.59\]
Correct Answer: D
Solution :
\[Y=\frac{\frac{F}{A}}{\frac{\Delta l}{l}}\] Given, \[\frac{F}{A}=\] stress \[=3.18\times {{10}^{8}}N{{m}^{-2}}\] \[1=1m,\]\[Y=2\times {{10}^{11}}N{{m}^{-2}}\] \[\Delta 1=\frac{A}{Y}=\frac{1\times 3.18\times {{10}^{8}}}{2\times {{10}^{11}}}=1.59\times {{10}^{-3}}m=1.59mm\]You need to login to perform this action.
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