A) \[N{{H}_{3}}<P{{H}_{3}}<As{{H}_{3}}<Sb{{H}_{3}}\]
B) \[{{H}_{2}}O<O{{F}_{2}}<C{{l}_{2}}O\]
C) \[{{H}_{3}}T{{e}^{+}}<{{H}_{3}}S{{e}^{+}}<{{H}_{3}}{{S}^{+}}<{{H}_{3}}{{O}^{+}}\]
D) \[B{{F}_{3}}<BC{{l}_{3}}<BB{{r}_{3}}<B{{I}_{3}}\]
Correct Answer: C
Solution :
[c] \[{{H}_{3}}T{{e}^{+}}<{{H}_{3}}S{{e}^{+}}<{{H}_{3}}{{S}^{+}}<{{H}_{3}}{{O}^{+}}\] (here, bond angle depends on electronegativity of central atom)
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