A) \[\frac{{{I}_{0}}}{4}\]
B) \[\frac{{{I}_{0}}}{8}\]
C) \[\frac{{{I}_{0}}}{16}\]
D) \[\frac{{{I}_{0}}}{2}\]
Correct Answer: B
Solution :
According to malus law, \[I={{I}_{0}}{{\cos }^{2}}\theta \] \[{{I}_{1}}=\frac{{{I}_{0}}}{2}\] \[{{I}_{2}}=\frac{{{I}_{0}}}{2}{{\cos }^{2}}45{}^\circ =\frac{{{I}_{0}}}{2}\times \frac{1}{2}=\frac{{{I}_{0}}}{4}\] \[{{I}_{3}}=\frac{{{I}_{0}}}{4}{{\cos }^{2}}45{}^\circ \Rightarrow {{I}_{3}}=\frac{{{I}_{0}}}{8}\]You need to login to perform this action.
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