A) \[1/4\]
B) \[1/2\]
C) \[3/4\]
D) \[1\]
Correct Answer: C
Solution :
[c] Here, \[f(x)=\frac{{{x}^{3}}-2{{x}^{2}}-x+2}{{{x}^{2}}-4},\,\,x\ne \pm 2\] Given that \[f(x)\] is continuous at\[x=2\]. \[\therefore \,\,\,\,\,\,f(2)=\underset{x\to 2}{\mathop{\lim }}\,\,\,f(x)\] Now, \[\underset{x\to 2}{\mathop{\lim }}\,\,\,\,\frac{({{x}^{2}}-1)\,\,(x-2)}{(x+2)\,(x-2)}=\frac{3}{4}\]You need to login to perform this action.
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