A) A and B have same specific heats
B) Specific heat of A is less
C) Specific heat of B is less
D) Nothing came be said.
Correct Answer: B
Solution :
[b] \[-\frac{dT}{dt}=\frac{4\sigma eA{{T}_{0}}^{3}}{ms}(T-{{T}_{0}})\] \[-\frac{dT}{dt}\propto \frac{1}{s}\]
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