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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 44

  • question_answer
    Equation of plane passing through line \[\frac{(x-1)}{2}=\frac{(y+1)}{-1}=\frac{(z-3)}{4}\]and perpendicular to the plane \[x+2y+z=12\]is given by \[ax+by+cz+4=0,\]then

    A) \[a=2,\,b=-9,\,c=5\]

    B) \[a=3,\,b=-6,\,c=5\]

    C) \[a=5,\,b=-2,\,c=9\]

    D) \[a=9,\,b=-2,\,c=-5\]

    Correct Answer: D

    Solution :

    \[\frac{x-1}{2}=\frac{y+1}{-1}=\frac{z-3}{4}\] \[\therefore \,\,ax+by+cz+4=0\]              ?..(i) \[\Rightarrow \,\,a-b+3c+4=0\] \[\Rightarrow \,\,a+2b+c=0\] \[\therefore \,\,9-4-5=0\] (Check by option)


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