A)
B)
C)
D)
Correct Answer: D
Solution :
[d] \[q=2C\varepsilon -\left[ 2C\varepsilon -\left( -C\varepsilon \right) \right]{{e}^{\frac{t}{2RC}}}\] \[=2C\varepsilon -3C\varepsilon {{e}^{\frac{t}{2RC}}}\] initial charge \[=-C\varepsilon \] final charge \[=2C\varepsilon \]You need to login to perform this action.
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