A) \[\frac{1}{2\pi }\sqrt{\frac{g}{2R}}\]
B) \[\frac{1}{\pi }\sqrt{\frac{g}{R}}\]
C) \[\frac{1}{2\pi }\sqrt{\frac{g}{R}}\]
D) \[\frac{2}{\pi }\sqrt{\frac{g}{R}}\]
Correct Answer: A
Solution :
[a] In equilibrium the particle is at the lowest position. Consider the system at an angular position\[\theta \].You need to login to perform this action.
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