A) \[O_{2}^{-},O_{2}^{2-}\]- Both diamagnetic
B) \[O_{2}^{+},O_{2}^{2-}\] - Both paramagnetic
C) \[O_{2}^{+},{{O}_{2}}\] - Both paramagnetic
D) None of these
Correct Answer: C
Solution :
\[O_{2}^{+}:\sigma 1{{s}^{2}}\sigma *1{{s}^{2}}\sigma 2{{s}^{2}}\sigma *2{{s}^{2}}\sigma 2p_{z}^{2}\] \[\pi 2p_{x}^{2}=\pi 2p_{y}^{2}\pi *2p_{x}^{1}=\pi *2p_{y}^{0}\] Number of unpaired electrons = 1, so paramagnetic. \[{{O}_{2}}:\sigma 1{{s}^{2}}\sigma *1{{s}^{2}}\sigma 2{{s}^{2}}\sigma *2{{s}^{2}}\sigma 2p_{z}^{2}\] \[\pi 2p_{x}^{2}=\pi 2p_{y}^{2}\pi *2p_{x}^{1}=\pi *2p_{y}^{1}\] Number of unpaired electrons = 2, so paramagnetic.
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