A) \[\frac{4}{5}\]
B) \[\frac{2}{3}\]
C) \[\frac{3}{5}\]
D) None of these
Correct Answer: B
Solution :
[b] \[D\Rightarrow {{p}^{2}}-4\left( \frac{p}{4}+\frac{1}{2} \right)\ge 0\] \[\left( p-2 \right)\text{.}\left( p+1 \right)\ge 0\] \[p\le -1\,or\,p\ge 2\] In 0 ^ p ^ 5, possible values of p are 2,3,4,5 Thus, probability \[=\frac{4}{6}=\frac{2}{3}\]You need to login to perform this action.
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