A) \[y=2\]
B) \[y=-1\]
C) \[x+y=2\]
D) \[x-y=2\]
Correct Answer: B
Solution :
[b] \[x-4x+6y+10=0\] \[\Rightarrow {{(x-2)}^{2}}=-6(y+1)\] circle drawn on focal distance as diameter always touch the tangent at the vertex i.e. the line \[y+1=0~\Rightarrow y=-1\]You need to login to perform this action.
You will be redirected in
3 sec