A) is equal to \[{{f}_{0}}\]
B) is less than \[{{f}_{0}}\]
C) is more than \[{{f}_{0}}\]
D) may be greater than, less than or equal to \[{{f}_{0}}\]depending on speed and length of train.
Correct Answer: A
Solution :
[a] \[f={{f}_{0}}\left( \frac{v\pm {{v}_{0}}}{v\pm {{v}_{S}}} \right)={{f}_{0}}\left( \frac{v+u\cos \theta }{v+u\cos \theta } \right)={{f}_{0}}\] where 'u' is speed of train.You need to login to perform this action.
You will be redirected in
3 sec