A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
[c] \[{{\sin }^{-1}}(\sin 1)=1,{{\sin }^{-1}}(\sin 2)=\pi -2\] \[{{\sin }^{-1}}(\sin 3)=\pi -3\] Hence, \[{{\sin }^{-1}}(\sin n)\] should be \[n-2\pi \]. \[\Rightarrow \,\,\,\,\,n=5,6,7,\] Hence, number of values of n is 3.You need to login to perform this action.
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