A) K
B) \[K/4\]
C) \[K/2\]
D) Zero
Correct Answer: C
Solution :
For path difference \[\lambda \], phase difference \[=2\pi \] rad. |
For path difference \[\frac{\lambda }{4},\] phase difference \[=\frac{\pi }{2}\] rad. |
As \[K=4{{I}_{0}}\] so intensity at given point where path difference is \[\frac{\lambda }{4}\] |
\[K'=4{{I}_{0}}{{\cos }^{2}}\left( \frac{\pi }{4} \right)\left( \cos \frac{\pi }{4}=\cos 45{}^\circ \right)=2{{I}_{0}}=\frac{K}{2}\] |
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