A) in AD, but not in BC
B) in BC, but not in AD
C) neither in AD nor in BC
D) in both AD and BC
Correct Answer: D
Solution :
Electric field will be induced, as ABCD moves, in both AD and BC. The metallic square loop moves in its own plane with velocity v. A uniform magnetic field is imposed perpendicular to the plane of the square loop. AD and BC are perpendicular to the velocity as well as perpendicular to applied field so an emf is induced in both, this will cause electric fields in both.You need to login to perform this action.
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