A) 64
B) 32
C) 16
D) 48
Correct Answer: B
Solution :
[b]: In the equation;\[_{S{{O}_{2}}}^{+4}\to _{S}^{0}\] \[S{{O}_{2}}\] acts as an oxidising agent, \[\text{Eq}\text{.mass}\,\text{of}\,\text{S}{{\text{O}}_{\text{2}}}\text{=}\frac{\text{Molar mass}}{\text{Change in oxidation number}}\] \[\text{=}\frac{64}{4}=16\] Twice of 16= 32You need to login to perform this action.
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