A) at rest
B) in uniform motion
C) in non-uniform motion
D) uniformly accelerated.
Correct Answer: D
Solution :
[d]:\[x=1.2{{t}^{2}},\] Velocity,\[v=\frac{dx}{dt}=\frac{d}{dt}(1.2{{t}^{2}})=2.4t\] Acceleration, \[a=\frac{dv}{dt}=\frac{d}{dt}(2.4t)=2.4=a\] a constant Thus the given motion is uniformly accelerated.You need to login to perform this action.
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