A) \[_{34}^{81}Se\]
B) \[_{35}^{81}Br\]
C) \[_{36}^{81}Kr\]
D) \[_{37}^{81}Rb\]
Correct Answer: B
Solution :
| Mass number of element = 81 i.e. \[p+n=81\] |
| Let the number of protons be x. |
| Number of neutrons \[=x+\frac{31.7}{100}\times x=1.317x\] |
| \[\therefore \,\,\,x+1.317x=81\] or \[2.317x=81\] |
| or \[x=\frac{81}{2.317}=35\] |
| Symbol of the element \[=\,_{35}^{81}Br\] |
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