A) \[\frac{1}{2}v\]
B) \[\frac{1}{\sqrt{2}}v\]
C) \[v\]
D) \[\sqrt{2}v\]
Correct Answer: C
Solution :
[c] By energy conservation, \[-\frac{GM}{R}+\frac{1}{2}{{v}^{2}}=0\] As R is doubled, m also doubles. So, v is the same.You need to login to perform this action.
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