A) \[\phi \]
B) \[[0,1/2]\]
C) \[\{0,1/2\}\]
D) \[\{0\}\]
Correct Answer: D
Solution :
\[\{{{x}^{2}}\}-2\{x\}\ge 0\] \[\Rightarrow \,\,\{x\}\,(\{x\}-2\}\ge 0\] \[\Rightarrow \,\,\{x\}\,\le 0\] or \[\,\{x\}\,\ge 2\] Second case is not possible. Hence \[\,\{x\}\,=0\]as \[\,\{x\}\,\le [0,1)\] Hence range of \[f(x)\] contains only one element 0.You need to login to perform this action.
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