A) \[\frac{1}{8}\]
B) \[\frac{2}{21}\]
C) \[\frac{1}{32}\]
D) \[\frac{1}{35}\]
Correct Answer: D
Solution :
By the diagram only 2 rectangles are formed ADEH, GFCB. |
\[\therefore \] number of favourable cases = 2 |
Total number of cases \[{{=}^{8}}{{C}_{4}}\] |
\[\therefore \] required probability \[=\frac{2}{^{8}{{C}_{4}}}=\frac{1}{35}\] |
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