A) 50-55%
B) 9-12%
C) 21-23%
D) 11-12%
Correct Answer: C
Solution :
| s-character \[\propto \] bond angle |
| For 25% s character (as in \[s{{p}^{3}}\]hybrid orbital), bond angle is \[109.5{}^\circ ,\]for 33.3% text{ }s\]character (as in \[s{{p}^{2}}\]hybrid orbital), bond angle is \[120{}^\circ \]and for 50% s character (as in \[sp\]hybrid orbital), bond angle is \[180{}^\circ .\] |
| Similarly, when the bond angle decreases below \[109.5{}^\circ ,\] the s-character will decrease accordingly. |
| Decrease in angle \[=120{}^\circ -109.5{}^\circ =10.5{}^\circ \] |
| Decrease in s-character \[=33.3-25=8.3\] |
| Actual decrease in bond angle \[=109.5{}^\circ -105{}^\circ =4.5{}^\circ \] |
| Expected decrease in s-character\[=\frac{8.3}{10.5}\times\] 4.5=3.56% |
| Thus, the s-character should decrease by about 3.56% |
| i.e., s-character = 25 - 3.56 = 21.44% |
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