JEE Main & Advanced Sample Paper JEE Main - Mock Test - 8

  • question_answer
    The half-life for radioactive decay of C-14 is 5730 years. An archaeological artifact containing wood had only 80% of the C-14 found in a living tree. The age of the sample is

    A) 1485 years          

    B) 1845 years

    C) 530 years            

    D) 4767 years.

    Correct Answer: B

    Solution :

    Radioactive decay follows first order kinetics, there-fore,
    Decay constant \[(\lambda )=\frac{0.693}{{{t}_{1}}/2}=\frac{0.693}{5730}\]
    Given,   \[{{R}_{0}}=100\]  \[\therefore \,\,\,R=80\]
    and \[t=\frac{2.303}{\lambda }\log \frac{{{[R]}_{0}}}{[R]}=\frac{2.303}{\left( \frac{0.693}{5730} \right)}\log \frac{100}{80}\]
    \[=\frac{2.303\times 5730}{0.693}\times 0.0969=1845\,years\]


You need to login to perform this action.
You will be redirected in 3 sec spinner