A) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
B) \[{{[Mn{{(CN)}_{6}}]}^{4-}}\]
C) \[{{[Fe{{(CN)}_{6}}]}^{4-}}\]
D) \[{{[Ni{{(N{{H}_{3}})}_{6}}]}^{2+}}\]
Correct Answer: D
Solution :
Hybridisation \[{{\underset{{{d}^{2}}s{{p}^{3}}}{\mathop{[Fe{{(CN)}_{6}}]}}\,}^{4-}},\] \[\underset{{{d}^{2}}s{{p}^{3}}}{\mathop{{{[Mn{{(CN)}_{6}}]}^{4-}}}}\,,\] \[{{\underset{{{d}^{2}}s{{p}^{3}}}{\mathop{[Co(N{{H}_{3}}]}}\,}^{3+}},\] \[{{\underset{s{{p}^{3}}{{d}^{2}}}{\mathop{[Ni{{(N{{H}_{3}})}_{6}}]}}\,}^{2+}}\] Hence \[{{[Ni{{(N{{H}_{3}})}_{6}}]}^{2+}}\] is outer orbital complex.
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