A) \[\frac{R}{4}\]
B) \[\frac{R}{3}\]
C) \[\frac{R}{8}\]
D) \[\frac{R}{5}\]
Correct Answer: A
Solution :
[a] Points A, B, C, D, E and F are equipotentials. From symmetry, points P, Q, R, S, T and U are equipotential and 1, 2, 3, 4, 5 and 6 are also equipotential. The circuit can be redrawn as \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,{{R}_{eq}}=\frac{R}{4}\]You need to login to perform this action.
You will be redirected in
3 sec