A) zero order
B) first order
C) second order
D) third order.
Correct Answer: D
Solution :
[d]:\[\frac{{{r}_{1}}}{{{r}_{2}}}={{\left[ \frac{2.4\times {{10}^{-2}}}{1.2\times {{10}^{-2}}} \right]}^{x}}\] \[8={{(2)}^{x}}\Rightarrow {{(2)}^{3}}={{(2)}^{x}}\therefore x=3\] Hence, the order of reaction is 3.You need to login to perform this action.
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