A) \[A=Mn{{O}_{2}}, B=C{{l}_{2}},C=NC{{l}_{3}}\]
B) \[A=MnO,B=C{{l}_{2}},C=N{{H}_{3}}Cl\]
C) \[A=M{{n}_{3}}{{O}_{4}},B=C{{l}_{2}},C=NC{{l}_{3}}\]
D) \[A=Mn{{O}_{3}},B=C{{l}_{2}},C=NC{{l}_{2}}\]
Correct Answer: A
Solution :
[a]:\[\underset{(A)}{\mathop{Mn{{O}_{2}}}}\,+4HCl\xrightarrow[{}]{{}}\underset{(B)}{\mathop{C{{l}_{2}}}}\,+MnC{{l}_{2}}+2{{H}_{2}}O\] \[\underset{(Excess)}{\mathop{3Cl}}\,+N{{H}_{3}}\xrightarrow[{}]{{}}\underset{(C)}{\mathop{NC{{l}_{3}}}}\,+3HCl\]You need to login to perform this action.
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