A) 0
B) 1
C) 4
D) None of these
Correct Answer: B
Solution :
[b] We have \[|A|\,\,=\,\,|B|=1\] and \[A.(adj\,A+adj\,B)=B\] \[\Rightarrow \,\,\,\,|A|.I+A.adj\,\,B=B\] \[\Rightarrow \,\,\,\,(I+A.adj\,\,B).B={{B}^{2}}\] \[\Rightarrow \,\,\,\,B+A.|B|.I={{B}^{2}}\] \[\Rightarrow \,\,\,\,A+B={{B}^{2}}\] \[\therefore \,\,\,\,\,\,|A+B|\,\,=\,\,|{{B}^{2}}|\,\,=\,\,|B|.|B|=1\]You need to login to perform this action.
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