A) \[1\]
B) \[2\]
C) \[3\]
D) \[4\]
Correct Answer: C
Solution :
[c] Given \[{{f}^{-1}}(2a-4)=\frac{1}{2}\] \[\therefore \,\,\,\,f\left( \frac{1}{2} \right)=2a-4\] Put \[x=\frac{1}{2}\] in \[f(x)=\sqrt[3]{\frac{9}{{{\log }_{2}}(3-2x)}-1}\] \[\Rightarrow \,\,\,\,\,f\left( \frac{1}{2} \right)=\sqrt[3]{9-1}=2\] \[\therefore \,\,\,2a-4=2\] \[\Rightarrow \,\,\,\,a=3\]You need to login to perform this action.
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