A) \[-\frac{Mga{{T}^{2}}}{2}\]
B) \[\frac{1}{2}M(g+a)a{{T}^{2}}\]
C) \[\frac{1}{2}M{{a}^{2}}T\]
D) Zero
Correct Answer: B
Solution :
Work done by normal reaction \[=Nh=M(g+a)\frac{1}{2}a{{T}^{2}}=\frac{1}{2}M(g+a)a{{T}^{2}}\]You need to login to perform this action.
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